Forum Discussion
Ron_Gratz
Aug 26, 2004Explorer
I don't want to mention the names behind these following quotes, but please read them: ----- So it seems both these quotes have it dead wrong by your definition - instead of 1/3 the 900 # weight, there will actually be a couple thousand.
Thomas,
I do not like to comment on things taken out of context. I have read the complete text of the two posts from which the quotes come.
I have no major disagreement with the gist of either post. Obviously, I would prefer to see reference to "distribution of hitch load" versus "distribution of tongue weight". The 1/3-1/3-1/3 distribution can only be achieved for selected combinations of TV/TT dimensions. However, it is relatively easy to produce an UP force equal to 1/3 of the "tongue weight" at the TT's axles. It is more difficult to get the TV's axle reactions to be equal. And, I do not think that is the primary objective of the WD hitch.
The full WD bar load (2000# in my example) does not get "distributed" as you have implied. The 2000# load causes an UP force of 300# (in my example) at the TT's axles. This causes the TV's front axle load to INCREASE by 612# and the TV's rear axle load to DECREASE by 912#.
Please note that I never have specified in my example what the "tongue weight" is. It does not enter into the distribution calculations.
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