Forum Discussion
toedtoes
Jul 21, 2015Explorer III
The correct calculation is:
X=((M1 + M2)/(G1 + G2))
M1 is the miles driven on the first leg; M2 is the miles driven on the second
G1 is gallons used on the first leg; G2 is gallons used on the second
So, if you went 200 miles on 40 gallons and then 200 miles on 20 gallons, you would have 5mpg for the first leg and 10mpg for the second leg, and the combined mpg would be:
X = ((200+200)/(40+20))
X = (400/60)
X = 6.6667
X=((M1 + M2)/(G1 + G2))
M1 is the miles driven on the first leg; M2 is the miles driven on the second
G1 is gallons used on the first leg; G2 is gallons used on the second
So, if you went 200 miles on 40 gallons and then 200 miles on 20 gallons, you would have 5mpg for the first leg and 10mpg for the second leg, and the combined mpg would be:
X = ((200+200)/(40+20))
X = (400/60)
X = 6.6667
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