24 volt to 12 volt converter

OldSmokey wrote:

BFL13 wrote:
"- battery V drop under load is halved on a % basis at 24v"

Is that true? It might be halved or doubled as such, but I would think on a Percentage Basis it would be the same. Please elaborate--my brain quit :)

assume T105RE with internal resistance of 0.001 Ohms per cell and 1200 Watt load

for 12V we have 6 cells so 0.001*6*100 A = 0.6 V
0.6/12*100% = 5 percent drop

for 24V we have 12 cells so 0.001*12*50 A = 0.6 V
0.6/24*100 = 2.5 percent drop

OK, East coast is back online with a cup of coffee, and even after sleeping on it I'm still confused by OldSmokey's example.

The 24V example uses four T105REs in series to get 12 cells and 24V.

But it appears that the 12V example only uses two T105REs to get 6 cells and 12V. What about the other two T105REs in parallel?

Wouldn't they effectively reduce the internal resistance by half and the V drop by half? Making the %V drop identical to the 24V example.