A AGC30 has a resistance of 0.002 ohms. Tell us how you're going to put 36V/35A or 6V/40A across one. What you're suggesting in nonsensical. Hint: Ohm's law is useful to know.
I=V/R. 6 volts divided by 0.002 ohms = 3,000 amps. Did I go wrong somewhere?
30 amps flowing at 12 volts makes about 10 percent of the heat across the fuse as 30 amps flowing at 120 volts.
The voltage the fuse sees has nothing at all to do with the voltage elsewhere in the circuit. The voltage across the fuse, and the heat it generates, is a function of the current and fuse resistance, nothing else.