Forum Discussion
Salvo
Nov 18, 2013Explorer
OK, let's say the energy dissipated by the thermistor is 1/2CV^2.
With C = 2400uF and V = 170V, we get E = 35.5 J. The part that's failing, per spec should be failing at 300 J. There's almost a factor 10 difference. That equation does not fit the bill.
Sal
With C = 2400uF and V = 170V, we get E = 35.5 J. The part that's failing, per spec should be failing at 300 J. There's almost a factor 10 difference. That equation does not fit the bill.
Sal
ken white wrote:Salvo wrote:
...The energy absorbed by the thermistor is I^2 * R * t. Where I is a exponential function of the RC time constant.
Sal
Calculate the RC time constant, and energy consumed, for me in a thermistor RC controlled circuit...
Since R varies with temperature, the Thermal Time Constant and absolute energy consumed is what is used...
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