Forum Discussion
ken_white
Nov 19, 2013Explorer
Salvo wrote:
...I = C * dV/dt = 2400 uF * 75V/5ms
I = 36A...
Sal
That current you calculated is the average current through the diode bridge and windings.
The period for a 1/4 cycle is 4.167 ms which makes the average current approximately 43.2 amps and the peak current approximately 2 times that amount or 86.4 amps.
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