Forum Discussion
ken_white
Sep 23, 2014Explorer
Salvo wrote:
C = 1500 F, 2.7V
i = C * dV/dt
i * dt = C * dV
Six in series:
i * dt = (1500F / 6) * 2.7V * 6
i * dt = 4050 As
i * dt = 4050 As / 3600 s/H = 1.1 AH
Six in series gives you 1.1AH. Nothing to write home about. What do they cost; perhaps $200 for 6???
I agree...
If you take this analysis a step further, discharging the capacitor bank to 0 volts is really not a viable use.
So if you assume 10.5 VDC as being the cut-off point for most electronics, then you only get about 0.4 A-H of capacity.
However, the impulse current that can be produced, and also needed during charging, is incredible...
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