Playing With DC to DC Boosters
http://www.ebay.com/itm/DC-DC-600W-12-60V-To-12-80V-Booster-Step-Up-Power-Supply-Module-/251667269211?pt=LH_DefaultDomain_0&hash=item3a9889c65b This little guy boosts voltage up to a limit of 12 am...
Forum Discussion
MEXICOWANDERER wrote:
.4 in occurred at 13.75 volts output on the WFCO = 5.5 watts INTO THE BATTERY
When the WFCO fed the DC to DC converter 177.6 watts went INTO THE BATTERY
Unless you feel the WFCO's potential of 792 watts is somehow insufficient to put 177.6 watts into the battery ? Minus the @ -10% efficiency loss 712 watts allows a lot of room to play with.
Someone is forgetting to include part a) of the equation which is 3,810 watts potential input into the WFCO (meaning AC). Which is sufficient to keep it happy.
AC feeds the wfco, the wfco feeds the booster, the booster feeds the batteries... I get it. But my original question was, and still is, how does the wfco suddenly supply more than its regulated 13.75 volts to the booster? If the wfco is set to regulate (i.e; limit) the voltage at 13.75v, how does more get thru? Does it suddenly lose its ability to regulate and serve only as a conduit for power? Does the booster convert the available dc current to dc voltage? How does 13.75v become 14.8v? The power has to come from somewhere, and as far as voltage is concerned, it isn't coming from the wfco. The wfco's voltage regulation is somehow being bypassed. Is it about watts in, watts out, not volts?
