Forum Discussion
Clay_L
Jun 21, 2014Explorer
The element will work okay on 120 volts but the watts will be 750 instead of 3000.
The resistance of the element will be about 19.2 ohms. At 240 volts it will draw 12.5 amps and the power will be 3000 watts.
At 120 volts it will draw 6.25 amps and the power will be 750 watts.
At 240 volts
W = VxA
A = W/V = 3000/240 = 12.5 amps
R = V/I = 240/12.5 amps = 19.2 ohms
At 120 volts
I = V/R = 120/19.2 = 6.25 amps
W = VxA = 120 x 6.25 = 750 watts.
As far as the leaking relief valve this is what the Atwood manual says to do to replace the air pocket that can help prevent drips.
"To replace the air pocket start by turning off the water
heater, shut off the incoming water supply
and open the closest hot water faucet. Pull the
handle on the pressure-temperature relief valve
straight out to allow the water to flow from the top
part of the tank. Once the water has stopped
flowing allow the handle on the valve to snap shut,
close the faucet and re-engage the water supply. "
The resistance of the element will be about 19.2 ohms. At 240 volts it will draw 12.5 amps and the power will be 3000 watts.
At 120 volts it will draw 6.25 amps and the power will be 750 watts.
At 240 volts
W = VxA
A = W/V = 3000/240 = 12.5 amps
R = V/I = 240/12.5 amps = 19.2 ohms
At 120 volts
I = V/R = 120/19.2 = 6.25 amps
W = VxA = 120 x 6.25 = 750 watts.
As far as the leaking relief valve this is what the Atwood manual says to do to replace the air pocket that can help prevent drips.
"To replace the air pocket start by turning off the water
heater, shut off the incoming water supply
and open the closest hot water faucet. Pull the
handle on the pressure-temperature relief valve
straight out to allow the water to flow from the top
part of the tank. Once the water has stopped
flowing allow the handle on the valve to snap shut,
close the faucet and re-engage the water supply. "
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