lorelec wrote:
ken white wrote:
What???
:?
We are talking about a 2% change of the voltage across the resistor, not a 2% (of some unknown reference value to compare against) voltage drop...
A 2% reduction of voltage across a resistor results in a 2% reduction of current through the resistor which is a 4% reduction in power lost...
The 2% voltage drop across your resistor is 0.02v, not 0.98v, which when plugged in to the P=V^2/R formula gives 0.0004w loss. 0.0004w is 2% of the input power (0.02w). Input power is the current flowing through the circuit (0.02a) multiplied by voltage across the entire circuit (1v).
A 2% drop in voltage across the resistor or a change in voltage across the resistor equaling a 2% change...
A voltage drop equaling 2% or 0.02 volts is only valid if its referenced to 1 volt.