Forum Discussion
2oldman
Sep 13, 2014Explorer II
Yes, I'm way off.
The tangent, (the rise over the run) of 3° is 0.052. For X feet of run, Y will be 0.052X.
At 16', that's (16x12)" x 0.052 = 9.984"
Wow, that is a lot.
The tangent, (the rise over the run) of 3° is 0.052. For X feet of run, Y will be 0.052X.
At 16', that's (16x12)" x 0.052 = 9.984"
Wow, that is a lot.
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