Forum Discussion
beemerphile1
Jun 05, 2015Explorer
If the load is ten feet from the fulcrum (axle) and the counter weight location is five feet from the fulcrum, double the weight is required for equilibrium.

ie;
F = 300 pounds
L = ten feet
X = five feet
then
W would require 600 pounds
F x L = W x X

ie;
F = 300 pounds
L = ten feet
X = five feet
then
W would require 600 pounds
F x L = W x X
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