Forum Discussion
naturist
Feb 04, 2016Nomad
What it takes to run the inverter is a function of how big the inverter is, whether PSW or MSW, and varies with load. By that, I think there is a certain loss even if there is no load, plus there is an inefficiency loss proportional to the load the inverter is serving. I wouldn't doubt that there is also a difference from manufacturer to manufacturer, but I don't know what any of these are, and I don't know how to go about guesstimating the sum of them for an arbitrary and unspecified inverter.
As for the equation, it is volts x amps = volts x amps. (110 volts) x (.45 amps) = (12 volts) x (solve for amps) OR (110 volts) x (.45 amps) / (12 volts) = (solve for amps).
As for the equation, it is volts x amps = volts x amps. (110 volts) x (.45 amps) = (12 volts) x (solve for amps) OR (110 volts) x (.45 amps) / (12 volts) = (solve for amps).
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