โOct-16-2013 07:32 PM
โJan-17-2014 01:46 PM
โJan-17-2014 12:15 PM
โOct-18-2013 01:46 PM
Salvo wrote:
You may have a measurement error. Where are you measuring Vmp? It should be directly at the panel, not at the controller.
In any event, the controller is starved for volts. This system should show better results if battery voltage is dropped to 12.5V.ktmrfs wrote:
Post #5
Parallel connection with 90ft of cable
Vmpptin=14.60V (TX3DMM)
Impptin=8.3A (DM330)
MPPT power in=14.60*8.3=121W
Vbat= 13.50V (TX3DMM)
Ibat=9.0A
Power to battery= 121.5W
โOct-18-2013 01:13 PM
ktmrfs wrote:
Post #5
Parallel connection with 90ft of cable
Vmpptin=14.60V (TX3DMM)
Impptin=8.3A (DM330)
MPPT power in=14.60*8.3=121W
Vbat= 13.50V (TX3DMM)
Ibat=9.0A
Power to battery= 121.5W
โOct-18-2013 12:56 PM
Salvo wrote:
WTF?12thgenusa wrote:
:R
โOct-18-2013 12:31 PM
12thgenusa wrote:
:R
โOct-18-2013 11:39 AM
โOct-18-2013 08:47 AM
CA Traveler wrote:
In Post #3 and Post #9 ktmrfs observed that serial panels produce the current set by the highest output current while the second shaded panel has reduced voltage.
I expected the current to limited by the shaded panel. Ie At 1000W a 8A panel would produce 4A at 500W based on the typical IV curves.
So how did ktmrfs see 4.1A in direct sun and 4.1A with one panel in the shade and reduced voltage for the shaded panel?
โOct-18-2013 08:24 AM
โOct-18-2013 08:08 AM
Salvo wrote:ktmrfs wrote:
Post #5
For series, cable power loss is I^2R, or V*I or V^2/R. To satisfy Salvo Iโll use V*I to calculate the power loss.
You haven't understood the previous discussion. I don't care how you calculate cable power loss. That's never been an issue.
Note that the parallel case with double the current has 4x the power loss, not double the power loss. (11.6W vs. 2.9W)
Abain, that's never been the issue. If you double current, cable power loss will be 4 times has high; no matter what configuration you use.
The intelligent way to figure out what size cable is needed is to use a 1% or 2% voltage drop rule of thumb. Whatever percent voltage drop is used, battery charging current will drop by same amount, not 4 times that amount.
Sal
โOct-18-2013 07:17 AM
ktmrfs wrote:
Post #5
For series, cable power loss is I^2R, or V*I or V^2/R. To satisfy Salvo Iโll use V*I to calculate the power loss.
You haven't understood the previous discussion. I don't care how you calculate cable power loss. That's never been an issue.
Note that the parallel case with double the current has 4x the power loss, not double the power loss. (11.6W vs. 2.9W)
Abain, that's never been the issue. If you double current, cable power loss will be 4 times has high; no matter what configuration you use.
The intelligent way to figure out what size cable is needed is to use a 1% or 2% voltage drop rule of thumb. Whatever percent voltage drop is used, battery charging current will drop by same amount, not 4 times that amount.
Sal
โOct-17-2013 10:06 PM
โOct-17-2013 08:45 PM
ktmrfs wrote:NinerBikes wrote:ktmrfs wrote:
Post #10
10)
This is for the case of resistance between the panel and controller. The effects of a long run with PWM controller between the controller and battery bank is not part of this investigation. That experiment is โleft as an exercise to the readerโ. Any volunteers???
How would this vary between MPPT and PWM, assuming same input voltage and same input amperage coming out of the devices to the battery? Obviously, the thicker the wire and shorter the run, being DC current, the lower the losses of watts/voltage and amperage. This is of concern if you use long runs of wire between portable solar cells and your batteries, I would assume?
As you noted, "short and fat wins over long and skinny every time."
However there are several things that come into play that could have different consequences on MPPT vs. PWM with a higher resistance between the controller and battery.
I gave it signficant thought, and really couldn't remotely convince myself what the effects would be on each system, so rather than speculate, I left it as "an exercise to the reader".
similar to some of the textbooks I had in college where MOST answers were in the back. the ones without an answer often said. "left as an excercise to the student" I quickly figured out that the prof that wrote the book didn't give the grad student solving the problems the solution, and the grad student finally gave up trying to solve the problem and "left it as an excercise to the student".
If anyone has some actual comparison data, or even data for increased resistance effects between the controller and battery for EITHER controller type, please post.
โOct-17-2013 08:40 PM
BFL13 wrote:harold1946 wrote:
My question is how were you able to maintain 70 degrees panel temperature throughout the testing?
He said 70F was ambient throughout and panels heated up right away so presume also maintained steady temp at 28C above ambient as he reported.
In my recent test of a panel, taking it out from the cool temp garage, it showed 37v Voc immediately, as rated, but very quickly that dropped to 36v as panel heated up. You could feel the glass was now warmer than it was at first. Happened fast.