BFL13 wrote:
Say your average DC amps is 5 at 13.6 volts all day. That is 68 watts. Efficiency is 85%, so input watts is 80 watts. Converter has PF of 0.7, so VA required is a steady 114.3 VA. Call it 1 AC amp at 115 volts.
Whatever that is in kw, for an hour is your kwh.
It is unnecessary to apply the power factor in this case; the electric company charges you for kWh, the actual energy used, and not kVAh. In the example, it works out to just shy of 2 kWh each day.
(For large commercial/industrial accounts the power factor is taken into account, along with peak usage and other such things...but not for residential users, at least anywhere that I've heard of.)