โJun-15-2016 03:52 PM
โJun-16-2016 07:35 PM
โJun-16-2016 05:43 PM
โJun-16-2016 12:45 PM
Almot wrote:beemerphile1 wrote:
Lots of different formulas people are posting making a simple calculation confusing.
Watts stays the same regardless of voltage.
130 watts divided by 120 volts equals 1.08 at 120vac
130 watts divided by 12 volts equals 10.8 at 12vdc
Just different ways to get the needed result.
AC amps multiplied by 10 is a good empirical formula for use without calculator - if you already know AC amps.
To get AC amps, you may divide 130 watts by 120 or 110, doesn't matter because real AC voltage is often in between.
But beware the jumping decimal point - it's been known to confuse even the brightest minds.
โJun-16-2016 11:54 AM
โJun-16-2016 11:18 AM
beemerphile1 wrote:
Lots of different formulas people are posting making a simple calculation confusing.
Watts stays the same regardless of voltage.
130 watts divided by 120 volts equals 1.08 at 120vac
130 watts divided by 12 volts equals 10.8 at 12vdc
โJun-16-2016 11:15 AM
โJun-16-2016 11:01 AM
โJun-16-2016 10:12 AM
smkettner wrote:DrewE wrote:Yes that pesky decimal jumped on me.smkettner wrote:
130w 110v resistive load might still draw 1 or 2 amps from a 12v battery.
A 130W 110V purely resistive load would be 93 ohms, and hence a current of 0.13A at 12V, about 1.5W. If this is an immersion heater, it will be a loooong time before the tea water is hot.
โJun-16-2016 09:42 AM
โJun-16-2016 09:26 AM
โJun-16-2016 07:54 AM
DrewE wrote:Yes that pesky decimal jumped on me.smkettner wrote:
130w 110v resistive load might still draw 1 or 2 amps from a 12v battery.
A 130W 110V purely resistive load would be 93 ohms, and hence a current of 0.13A at 12V, about 1.5W. If this is an immersion heater, it will be a loooong time before the tea water is hot.
โJun-15-2016 10:58 PM
โJun-15-2016 10:53 PM
smkettner wrote:
130w 110v resistive load might still draw 1 or 2 amps from a 12v battery.
โJun-15-2016 09:27 PM