It is all pretty confusing for me. Here are my numbers at the scale (full tank of diesel and my wife next to me in the passenger seat) and on the inside of the driver door sticker:
Steer axle: 4220 lbs
Drive axle: 2900 lbs
Gross weight: 7120 lbs
The sticker on the inside of the driver door says:
GVWR: 9200 lbs
GAWR Front: 4670 lbs
GAWR Rear: 6084 lbs
My wheels are rated at 3,000 lbs as per manufacturer (they are not the stock wheels but wheels that the first owner put on the truck). Tires are Nitto load range E, 3750 lbs capacity (so they overshoot the wheels).
Can someone guide me through the exact calculation used to find out how much weight can be put on the tongue in the truck bed?
I am asking for the following case: we (God forbid) get into an accident and are taken to the scales. The scales put out a set of numbers and my insurance company gets these numbers. Based on these numbers they calculate that I am within carrying capacity and decide to honor insurance. Or they decide I am grossly overweight and decide not to honor it. I don't want to drive around thinking I am insured when I am not. In addition, breaking distance, safety etc. play a role. I don't want to drive around, for example, 2,000 lbs overweight and that increases my breaking distance by X feet.
Thanks!
According to my math a GVWR of 9,200 lbs minus scale wt 7,120 gives you a payload of 2,080 lbs. That would be your max hitch wt.
You need something close to 15% or better of the trailer wt. on the hitch. The trailer mfg should be able to give you some numbers for the hitch weight and with a lot of math you can figure out what the loaded hitch weight will be. Find a pilot to help with that. They have to do it all the time. :)
Some of the information in a previous post was inaccurate and could easily lead to confusion. You seem to have a good handle on it.
