dockmasterdave wrote:
---For every foot the trailer extends above the roof line of the truck, it approximates another thousand pounds of towed load.
Has anybody else heard this ratio, or does it sound close to you?
It depends on how you're moving the added load.
According to
Aerodynamic Drag, the drag force at 60 mph on a frontal area of 8 sq ft (1' high by 8' wide) with a drag coefficient of 1.2 is about 88 lbs.
The extra power required to overcome this added force at 60 mph would be about 14 hp.
Now, let's ask how much additional load could be carried inside a trailer on a level surface at 60 mph so that the additional power required to overcome the added tire rolling resistance would be 14 hp.
Assuming a rolling resistance coefficient of 0.01 for a truck tire on a smooth surface
(see Rolling resistance), the answer would be about 8750 lbs.
Or, we could ask how much additional load can be moved up a 6% grade at 60 mph with a power expenditure of 14 hp. The answer would be about 1250 lbs.
About 2 hp would be used to overcome the added rolling resistance, and about 12 hp would be used to move the extra 1250# up the 6% grade.
So the ratio between added height and equivalent added weight based on horsepower can vary widely depending on how you are going to move the added weight.
If you're concerned about the extra power required by additional frontal area, you can achieve a significant reduction in required power by reducing speed.
Power required to overcome aerodynamic drag force at 55 mph is about 50% of that required at 70 mph.
Ron