Forum Discussion
BFL13
Oct 30, 2013Explorer II
Not sure if we are talking about the same thing but using the glass half full or half empty way of looking at it and getting mixed up.
The wire just adds some R to what the charger "sees" as the battery. So the thin wire makes it seem like the battery bank is smaller than it is (lower AH total capacity)
This has the same effect as increasing the charging rate (initial charging amps wrt battery capacity) which makes the battery reach Vabs at a lower SOC for same Vabs. So amps will taper sooner in SOC, but you still get a faster charge in comparison with using a lower initial rate and a higher SOC where tapering starts.
Once you are at the same SOC and battery voltage, the acceptance rate is the same and charging times will be the same from then on to fully charged.
Sorry, I have to show this with my ugly graph again, since it is too hard to describe in text:

Now you might say that since the thin wire makes the battery seem smaller than it really is, that you will take longer to charge it since it is bigger than it seems.
The wire just adds some R to what the charger "sees" as the battery. So the thin wire makes it seem like the battery bank is smaller than it is (lower AH total capacity)
This has the same effect as increasing the charging rate (initial charging amps wrt battery capacity) which makes the battery reach Vabs at a lower SOC for same Vabs. So amps will taper sooner in SOC, but you still get a faster charge in comparison with using a lower initial rate and a higher SOC where tapering starts.
Once you are at the same SOC and battery voltage, the acceptance rate is the same and charging times will be the same from then on to fully charged.
Sorry, I have to show this with my ugly graph again, since it is too hard to describe in text:

Now you might say that since the thin wire makes the battery seem smaller than it really is, that you will take longer to charge it since it is bigger than it seems.
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