Forum Discussion
Almot
Feb 17, 2016Explorer III
196 A current is too much for your batteries. I don't want to turn this into "50 ways of making coffee" (myself gave up coffee long time ago), but this is the case when you have to sacrifice either Keurig, or the silent way of inverter - and run a generator every single time you run Keurig. Or - double the battery bank.
Here is why:
6.88 AH calculated in other post doesn't include Peuker effect - abrupt increase of AH "actually taken" from the battery at high currents, compared to calculated current*time. Because of this high current, 196A becomes at least 350A of "Peukert corrected current", possibly 400-500A, and can be as high as 1000A for some flooded batteries.
400A*0.05 hr = 20 AH every time. With 225 AH bank you only have 112 AH available. Run your Keurig 5 times and the battery is down to 50%.
This is - if your batteries are still in a good shape and voltage won't drop so low that you won't be able to run Keurig at all.
Here is why:
6.88 AH calculated in other post doesn't include Peuker effect - abrupt increase of AH "actually taken" from the battery at high currents, compared to calculated current*time. Because of this high current, 196A becomes at least 350A of "Peukert corrected current", possibly 400-500A, and can be as high as 1000A for some flooded batteries.
400A*0.05 hr = 20 AH every time. With 225 AH bank you only have 112 AH available. Run your Keurig 5 times and the battery is down to 50%.
This is - if your batteries are still in a good shape and voltage won't drop so low that you won't be able to run Keurig at all.
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