full_mosey wrote:
BFL13 wrote:
Worth a try. The draw from the generator does go down with output DC amps. I don't know if the divide by 10 rule would apply here or not.
...
I use a Magnum 1000W/50A inverter/charger and watch the KAW closely when charging. To estimate charging Amps, I divide the Watts by 20, not 10.
The manual says "7AAC Input current at 50A rated output", which would indicate 840W. 840/50 = 16.8W/A. I should divide by Watts by 16.8, but it is so easy to divide by 20.
Unfortunately, I don't have any DC measurements.
HTH;
John
Not sure what to make of that. A charger doing 50 amps DC would be rated around 850w but that would be before the PF is applied. Say PF is 0.7 then VA would be 7a x 120v = 840w x 100/70 = 1200VA from the power source.
I don't know how it goes with an inverter/charger what watts it is reading. ISTR the charger would only work on pass through 120v, so how can the inverter read the 120v watts? Just asking, I have no clue--good chance to learn something here! :)
How do you see it? Does the manual have anything more that would help? Is the charger actually a 50 amp with PF correction? (that would be low amps to have that--I/Cs with 100a chargers do have PF correction though.
