time2roll wrote:
larry cad wrote:
I would be interested in your calculation to support this statement. I assume you know the internal resistance of the two types of batteries, and also the resistance of the jumper wire between the two series sets of batteries. No doubt you included the resistance of the series jumpers as well.
By the way, the calculated resistance of the jumper wires, (both the series connections and the parallel connections) are .000047 ohms. If I were ever to pull full load (i.e. 400amps) through any one of those jumpers, the voltage drop calculates out to be .0188 volts DC which is .00156% of the 12vdc
http://www.smartgauge.co.uk/batt_con.html
Thanks but unfortunately the four diagrams do not apply to my situation as your diagrams would have to be used for 4 each, 12vdc batteries rather than my 4 each, 6vdc batteries. I have to "create" 2 each 12vdc batteries by tying 2 of the 6vdc batteries in series then the last 2 6vdc batteries in series, then take both sets of series batteries and tie them in parallel. That particular application is not shown in your post.