StirCrazy wrote:
you should keep them the same so it ballances the amprage between each battery. if you use the situation above with one 100 amp battery and one 200 amp battery in parralell and you put a 100 amp load on it, yes the battery voltage will drop the same but the capacity of the 100amp battery will drop twice as fast if you have a 50amp BMS on each battery (for example) so once the 100amp battery gets down to the cut off voltage (10% in my battery) it will shut off trying to throw all the load to the other battery but since that load is twice the amount alowed by the second battery the BMS will shut it off on protection also.
Again I call BULL. You are assuming that each battery provides 1/2 the load current. This is beyond belief, it very simply WILL NOT HAPPEN in fact IT CAN NOT HAPPEN. for as you yourself admitted the voltage drops as the SOC goes down. Thus the if you put a 100 amp load on the pair the 100 amp battery will not provide 50 amps but 33.33333333 and the 200 amp will provided 66.6666666d The current divided PRECISELY according to the capacity of the batteries.
This is the ONLY way it can happen. for the battery with the higher state of Charge will provide ALL the current till the SOC's match (Or nearly all)
This is the very MYTH that I warned about in my earlier post.
Now instead of electricity think water
you have two tanks side by side
one tank holds 1,000 gallons and the other thank which is the same height and the same depth but TWICE as wide. holds 2,000 gallons.
They are connected at the bottom by a "T"
When you draw water off the "T" which one is going to hit empty first?
Now think about this... if the water is HIGHER in one tank, that tank pushes harder and will provide all the water till the levels are the same. then they split the load 1/3 2/3
It is exactly how the batteries work.
The only warning is the charger
If you set up a charger for 300 amp hours and one of the batteies goes HIGH RESISTANCE... I'm not sure what happens (Due to the BMS systems. they may protect or not)