Forum Discussion
HiTech
Dec 15, 2012Explorer
red31 wrote:
Turn on one light at dusk and try.
2-3 kWh/m^2/day, so 3*4amp = 12ah/day
http://rredc.nrel.gov/solar/old_data/nsrdb/1961-1990/redbook/atlas/
Very cool! What conversion did you use to get from radiation intentensity to amps or watts? Looks like my guess of 10-15 based on partial day and partial shade data is not way off.
Using that site this should be the winter solstice radiation for the whole country:
December minimum radiation intensity on a flat panel
Jim
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