Forum Discussion
grizzzman
Mar 20, 2015Explorer
Empty Nest, Soon wrote:
Grizzzman – My concern was at what point does the cross-sectional area of the conductor (the bracket) become small enough that it gets hot from resistance and perhaps burns in two? Same principle as a fuse.
But, I suppose if the voltage drop across it is so negligible, then the heat generated from the current passing through will also be negligible?
Wayne
Yep you got it. Voltage drop is the measurement used to decide if a conductor can handle the amps you want to put through it. And the higher the drop across the conductor the more heat it will generate. To put into perspective at 200 amps and 14 volts the voltage drop on your bracket would be about .0079. If you are using a 500 amp shunt and passing 200 amps at 14 volt its voltage drop would be .020. It is this calibrated voltage drop that the TM 2030 uses to decide how many amps are being used.
Good luck with your project
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