Here is a snippit from an article I read:
"Note that single-phase generators are usually rated for loads with PF=1, so their W and VA ratings are the same. Since typical appliances have PF=0.6-0.8, their VA consumption is 25-60% greater than their wattage. That's why generator output rating should be much greater than the net wattage of such motor-driven devices. For example, for 700 W load with PF=0.7 you need at least a 700/0.7=1000 W generator. Fortunately, nowadays an appliance's nameplate usually states its maximum current rather than wattage, so you don't need to know its PF: you just multiply the value of the current by nominal AC voltage (120V in US) to get the VA. For example, if your single-phase appliance is rated for 10 A maximum, it may consume up to 120×10=1200 VA. This is the number you should use when you do sizing."
It seems I should simply multiply the pm's 10a rating by the generators output voltage.
... Assuming the genset puts out 120v, the pm-45 would use up 1200w out of 1600, and draw 10a out of the 13.3a available?
