ken white wrote:
Salvo wrote:
Here's what you said:
"As I mentioned in a previous post, a 2% voltage drop is a 4% power loss."
This is wrong! A 2% voltage drop is equal to a 2% power drop and a 2% drop in charging current.
It can't get any simpler than that!
A 2% voltage drop does not turn into a 4% power drop.
Sal
ktmrfs wrote:
What I was referring to is the case of two series vs. parallel panels. the cable power loss is 4x greater in the parallel case vs. series case not double.
Power is also equal to V^2/R so if the resistance of the cable/wire does not change, then doubling the cable voltage drop creates a factor of 4 increase in power loss for the cable.
Maybe that is what he was trying to say?
yup, see my post above for an example comparing power loss in series vs. parallel hookup