Salvo wrote:
Ken- I had nothing agains that post. I didn't even respond to you until you started arguing with me. Here's the issue:
ktmrfs states a 2% voltage drop equates to a 4% power drop.
This is absoultely wrong. You chose to defend ktmrfs.
BTW, stay away from personal attacks!
Sal
I just can't help myself...
;)
Here is a simple example to show ktmrfs is correct.
Assume a resistor of 1 ohm has a voltage of 1 volt across it, power would be equal to (1V)^2/1 Ohm or 1 Watt.
Reduce the voltage to 0.98V (a 2% drop in voltage) and power is equal to (0.98V)^2/1 Ohm which is equal to 0.9604 or 96.04% of the original power - close enough to 96% for me.