ktmrfs wrote:
power loss in a wire also follows the same square law change. again, if R is held constant, then the power drop is related to current squared or voltage drop across the wire squared. double the current in a wire and the power loss in the wire will quadruple.
True, but when R is the independent variable (as it is in the case of choosing wire size), then it has a linear 1:1 relationship with power loss if we keep V or I constant. If we keep I constant, as it usually is with a solar panel connected to a battery, then an increase in R (smaller gauge wire) will cause P (power loss in the wire) to increase by an equal percentage.