Forum Discussion
Mike_Stanbro
Jan 05, 2014Explorer II
Something else to keep in mind about motor currents...
The power required to lift a camper/trailer or operate a slide-out mechanism is essentially constant while the voltage of the battery supplying the power is not. Electrical power = volts x amps. As the battery voltage goes down, the current demand increases in a linear fashion to deliver the same amount of power.
In a previous post SkiPro3 said that he measured the current of each jack motor on his 855S to be 8 amps. If the voltage of the battery drops from 12.5 volts (charged) to 10 volts (discharged), the current to operate the jack motor will go from 8 amps to 10 amps.
Here is the math:
12.5 volts x 8 amps = 100 watts
100 watts/10 volts = 10 amps
So SkiPro3, if you don't want to blow those 10 amp fuses you installed, make sure your batteries are always well charged. Or, you could install 10 amp, auto-reset circuit breakers and not worry about it. Just a suggestion.
The power required to lift a camper/trailer or operate a slide-out mechanism is essentially constant while the voltage of the battery supplying the power is not. Electrical power = volts x amps. As the battery voltage goes down, the current demand increases in a linear fashion to deliver the same amount of power.
In a previous post SkiPro3 said that he measured the current of each jack motor on his 855S to be 8 amps. If the voltage of the battery drops from 12.5 volts (charged) to 10 volts (discharged), the current to operate the jack motor will go from 8 amps to 10 amps.
Here is the math:
12.5 volts x 8 amps = 100 watts
100 watts/10 volts = 10 amps
So SkiPro3, if you don't want to blow those 10 amp fuses you installed, make sure your batteries are always well charged. Or, you could install 10 amp, auto-reset circuit breakers and not worry about it. Just a suggestion.
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