Do the math for me...

130w /110 = 1.18 amps (Rule: Watts= amps x volts)

Battery draw at 12v is approx. 10x what the 110v side draws, therefore, 10x 1.18=11.8 amps. (Rule: watts are conserved. Voltage is 1/10 of 120, so amps must be 10x)

And it's not "amps per hour", it's just amps. If you ran it for one hour, that's 11.8 amp-hours.

130.000 watts / 12.0000 volts yields amps, you do the math.
divide by .8 or .9 for inverter effiency

130 ÷ 10 = 13 amps

Thanks to all!

Eric

smkettner wrote:
130 ÷ 10 = 13 amps

Wrong...It's 130 ÷ 110 = 1.18 amps

Since you are running 120V appliance from 12v battery, you will need inverter.
Depends on quality, those will take additional +- 10%
As you can see those can be only approximate numbers.
We don't know if the voltage is 120 or 110 volts.
Nor 12 or 12.5 volts

0. Plug it into 110.

allen8106 wrote:
Wrong...It's 130 ÷ 110 = 1.18 amps

The question was "from 12V battery". Therefore, about 12-13 amps with inverter losses.

Hooked up straight to 12V, AC appliance will draw nothing, of course :)

130w 110v resistive load might still draw 1 or 2 amps from a 12v battery.

If it's a vacuum cleaner split phase motor like a fan then y'all best take a deep breath and sharpen your pencils. Split phase and modified sine wave are like scotch with a vermouth chaser.