Forum Discussion

icanon's avatar
icanon
Explorer
Jan 30, 2015

Calculating weight distribution requirements?

Hi everyone :-) First post and excited!!!

Wondering how do you calculate what WD is required for your rig? Say for example the TT (loaded) tongue weight of 950lbs do you add the weight of your WD/Sway to the tongue weight of the TT? So 950bs + 40lbs (WD/Sway) = 990lbs therefore I need a WD capacity of at least 1,000? Am I correct or am I doing it all wrong?

Also does a vehicle with 4 corner air suspension (self leveling) make any difference to the equation?

Thanks for your input.
  • icanon wrote:
    kennyzzz wrote:
    some reading for you, hope it helps.
    http://www.rv.net/forum/index.cfm/fuseaction/thread/tid/25572537.cfm

    ps it helps if you tell what you tow with.
    ps # just trying to help


    Thanks I'm reading this link now.
    Towing with a Dodge Ram Laramie 1500 Quad cab 5.7 Hemi with 3.92 diff. with 4 corner air suspension. My new trailer in which I'll be picking up this spring is a Kodiak 290BHSL with a unloaded TT of 6,005lbs and a TW of 781 lbs.

    Assuming I load it to the max load of 1,500lbs therefore I'll be around 7,500lbs but the TW is were I'm trying to respect to a max of 960. After reading many blogs and forums about whether or not to install a WD and/or Sway control has me wondering what route to go? I believe and my thoughts that there is no harm in installing a system like equalizer only to benefit if there is any, any problems that can occur out on the road.

    Thanks for the reply. Will update my signature to reflect my rig :-)


    What is the Ram receiver hitch rated for? The one on my F150 is only rated for 1050 lbs. If your tongue weight is over 500 lbs., you need a WD hitch.