Finally weighed the TV and TT together... ugh

AH64ID wrote:
---The longer the wheelbase the harder it is to transfer 100% of the weight back.

With a longer wheelbase -- less load is removed from the TV's front axle to begin with.

The amount of downward force which must be exerted by the WD bars to restore 100% of the weight is not dependent on wheelbase.

For:
a = TV wheelbase
b = TV ball overhang
c = distance from ball to midpoint between TT's axles
d = effective length of WD bars
TW = TT tongue weight
BARLOAD = vertical load exerted on A-frame by a single WD bar

load removed from front axle = TWxb/a

load restored by WDH = (2xBARLOADxd/c)x{(b+c)/a}

Making the load restored equal to load removed (100% FALR) gives:

BARLOAD/TW = (b/d)x{c/(b+c)}/2

For a typical TV/TT/hitch: b=60, c=240, and d=30

Then: BARLOAD/TW = 60/30x{240/(60+240)}/2 = 0.8

Or: For 100% FALR, each bar must be adjusted to produce a load equal to about 80% of tongue weight -- independent of TV wheelbase.

Ron