BFL13 wrote:
Using the calculator above, my 0.6v drop with 12v works with cu #1AWG at 24 ft round trip at 100 amps.
If I just change to 24v and 50 amps, leave the wiring the same, voltage drop should be half (not double) but percentage drop is 1/4.
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The calculator isn't switching from parallel to series configuration. But that's what we are doing with the batteries (or resistors).
When you take two resistors/batteries (each with R internal resistance) and put them in parallel, the overall resistance is halved. In series the overall resistance is doubled.
In parallel, overall current is 2x that in series with that same load in watts. Say 100A at 12V and 50A at 24V at 1200W (VA).
So Vd = 100 x R/2 = 50 x R, at 12V
and Vd = 50 x 2/R = 100 x R, at 24V
So twice the voltage drop when configured in series at 24V when compared to configured in parallel at 12V. But the same % drop and same wattage drop. Theoretically ...