Im still trying to wrap my head around 2 batteries in series, powering a light bulb for months, and only 1 battery died.
Now given i have not taken SG measurments. I picture the 2 batteries as 1 single larger battery. Since it was two 8v that are 4 cells each lets call it an 8s battery.
Its so weird how 4 of those cells were drained to zero. While the other 4 were depleted but not dead. While not identical in age and brand they are similar in capacity. I dont know if the voltage regulator and LED lights were still drawing small amounts of power when i discovered the dead battery. Its possible the battery that was drained low was on its way to being completely dead too. But the lights have been on for months. I would have expected 2 dead batteries. Maybe the voltage regular broke and stopped drawing power. Variables
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Actually i was sitting here thinking. I think thats the answer....the voltage regulator. It has a little potentiometer that you turn to adjust output voltage. I bet as the battery voltage dropped, eventually the output voltage got down to zero. Thats why the 2nd battery was not drained to zero.
If it was a standard light bulb i would most likely have had 2 dead batteries? Its still interesting how the 1 year old battery is the battery that drained first. At some point i will have to weight the difference between the newer off brand battery and the old Trojan 8v.