wwest wrote:
LOTS of bad, incorrect, information here, throughout the thread...
Malarkey, not desirable, but the more critical issue is whether or not the compressor motor starts reliably each and every time without the internal self-resetting CB "popping".
The misinformation is mainly from you...
The motor's load may be considered fixed, so the same work (or
power/energy delivered) is performed when operated.
No, the A/C compressor motor's load changes, increases, as head pressure rises. Turn off the A/C while the compressor is cycling, turn it back on quickly, the motor likely will not restart. The motor's internal HEAT sensitive CB will begin cycling on and off until the head pressure declines enough to allow the motor to restart. Or the house CB pops..This statement was made in an effort to keep the analysis simple since the motor was sized to operate, or trip off, under these various conditions.
When the motor's input voltage is low, the input current draw must increase in an effort to perform the same work.
YES!Whew, we agree...
This increased current draw causes increased internal heating and reduced motor efficiency, which overheats the windings and core and can cause premature failure.
NO! P=IE, POWER (WATTS) = AMPS times VOLTAGE, reduce the voltage and increase the current, POWER doesn't change,....
But PF, Power Factor does.. The increase in current flow results partially from low power factor, the load begins to look more inductive than resistive. So, yes, current flow increases, but since that current flow is now "more" out of phase with the applied voltage, apparent power (derived strictly from voltage and current flow measurements) is greater than ACTUAL power consumption.
Example: Connect a high value bi-polar capacitor directly across the 115 volt AC line. A measure of power, current times voltage, will indicate power consumption when there is virtually NONE! Actually, when the losses increase due to increased current through the windings and core, the efficiency goes down which means more input power is required to perform the same output work.
We are not talking VAR's here but real power (work)...
Power factor in a motor is a function of the motor's inductance, resistance, losses, and work performed.
Can you give me one example of how the motors inductance changes just by increasing current?
A lower PF would mean that inductance has increased, or less losses and less work is being performed which doesn't happen under normal operations.
None of this malarkey occurs.
PF increases with increased load and decreases when unloaded...
I think you need to revisit some of your hypothesis statements.