mlslcan wrote:
A tire is basically a torus (doughnut shape) object. For your desired use using that as the basis of the calculation will be close enough. The following link is a calculator and diagram that you can use to calculate the voulume. Notice that the diameter is to the middle of the tire and not just the rim diameter. I converted your tire size to inches (235mmm = 9.25 inches) then used that to get the height of the tire (.75 x 9.25 = 6.94 inches) divided that by 2 to get to the middle of the tire (6.94 / 2 = 3.4) then added in the rim diameter (16 + 3.4 = 19.4) to use as the diameter of the torus. I used the width (9.25 inches) as the "band width" of the torus. This gives 4095.6 cu inches for the volume.
Volume of a torus
As stated above this is the volume of the tire not the volume of air required to achive x psi in the tire. If you take the volume of the cylinder (cylinder volume) you can determine which cylinder will work for you.
Mike
Edited to correct grammer where I added in the rim diameter
Honey, is that you? :B
Can't help but ask- the O.P.'s question and the above answer sounds EXACTLY like a typical exchange between my Scientifically Challenged self and my Engineer Husband. As is usual with us, the above is an excellent answer, completely on point- and likely totally incomprehensible to the questioner.
My next question would typically be:
If I squish the air a little harder before putting it in the tire can I cram more in ? :@
