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Snowman9000's avatar
Snowman9000
Explorer
Oct 29, 2014

Measuring V loss during charging

I know that a discharged battery can pull down the voltage at the charger. I was trying to measure voltage loss in my converter wiring, switches, etc. The two 105 AH batteries were 12.13v prior to charging. It's a WFCO converter with horrible OEM wire routing.

So getting started:
Charging current was 15A at time of measurements*
V at converter outputs was 13.60
V at batts was 13.06

I repeated this process with a HF charger clamped to the batts, with the converter off, and saw a similar V drop at the batteries versus at some Anderson power pole connectors in the middle of the HF cable. It went from 14.00v at mid-cable to 13.43v at the battery clamps and batteries.

I also did it with a Turnigy power meter in between the halves of the HF cable. Similar results. There were drops of 0.05v at each half of the two sets of power pole connectors. And apparently the Turnigy meter itself dropped 0.1v. But the big V drop, 0.7v less than the point 3 feet upstream, was registered at the battery.

How can a person tell how much of the V difference is loss due to wiring etc.?

*Charging started with amps in the mid 20's, but tapering right away. It was fairly steady at 15-ish when I took my measurments.
There were no significant other loads on the converter during this charging. Let's leave the WFCO discussions for another thread. Thanks.

64 Replies

  • Quote: "Measure the resistance of the circuit."

    To elaborate on this: In this case the resistance is too small to be measured directly with a typical ohm meter because the current generated by the typical ohm meter is so little. Best to measure (an estimate is probably close enough) the current in the wire and the end to end voltage drop in the length of wire (as suggested above). In this way you are creating a "high current" ohm meter which over comes the standard VOM ohm meter by using brute force (15 Amps as opposed to a few milliamps).
  • The resistance was .036 ohms. Find a chart with the wire size and resistance per foot. I would say you have no issues. Things must be shiny clean and tight because 12 volts has very little push to overcome resistance.
  • Voltage drop in cables is simply the difference between the voltage measured at the power supply and the voltage measured at the battery.

    If you want to measure directly, just put one leg of your voltmeter on the battery and the other on the same wire at the output of the power supply.

    Steve