Bendder wrote:
---What I would like to know is the downward force at the pin by the diff and also the forces on the bearing rollers? any help would be appreciated
Mark, welcome to Open Roads Forum.
You can get a good estimate of the downward force at the pin by using the following leverage equation:
Force * (61.5" + D) = TW * D or Force = TW * D / (61.5 + D)
where 61.5" = distance from pin to ball per your diagram,
D = distance, in inches, from ball to midpoint between TT's axles, and
TW = tongue weight.
The above equation assumes there is no significant vertical force exerted on the roller bearings.
It is my understanding that the WD bars should be adjusted to minimize this force.
For your information,
this thread contains a wide-ranging discussion of the PullRite hitch (and a lot of other stuff).
This web page by ORF member, Steve Rankin, shows his installation process.
BTW, you did a great job on the PullRite diagram -- except the downward force on the ball (which you show as 1000#) is equal to the TW plus the downward pull exerted by the two lift chains minus the amount of load transferred to the TT's axles.
For your example the downward force on the ball might be approximately 1000+2000-200 = 2800#. (The 200# depends on "D" in the above equation.)
The upward force exerted on the hitch head via the front ends of the WD bars would be 2000#.
The net force exerted on the hitch head, and transmitted to the pin, would be about 800#, if we ignore the weight of the drawbar which extends from hitch head to the pivot pin.
Ron
