Working solar panel vs. idling panel-what changes at panel?

If the panel is 14% efficient, then somehow 14% of the light energy falling on it would have to be exported..right?

If a panel is in open circuit, no energy is exported.

I'm just trying to get a handle on how that shows up at the panel. If the panel had exact same reflectivity, and measured exact same temperature (or higher), yet it was giving 14% of the light falling on it as electrical energy-then it would seem we have something which violates the law of physics...