โDec-28-2014 03:30 PM
โJan-01-2015 08:31 AM
Bud
USAF Retired
Pace Arrow
โJan-01-2015 08:22 AM
Water-Bug wrote:frizzen wrote:
Since the resistance of 8 gauge AWG copper is .0007 ohms per foot, I think we can ignore the voltage drop for a couple of 2 foot jumpers.
Especially since it's usually thicker than that and the wire from the charging inverter is usually 5X longer and 5X thinner.
โDec-31-2014 08:24 PM
frizzen wrote:
Since the resistance of 8 gauge AWG copper is .0007 ohms per foot, I think we can ignore the voltage drop for a couple of 2 foot jumpers.
โDec-31-2014 04:39 PM
โDec-31-2014 04:08 PM
Coach-man wrote:Whatever you say...
I am sorry, if you are relying on the extra battery cables to transfer power to the other cells, they have additional resistance, therefore using OHMS law voltage times current divided by resistance, you will have less current gowing to the othe cells if you connect both positive and negative to the same set of cells! Yes you have the same resistance drop across both sets of cells if one positive to one set and negative to the other set, but all cells will be the resistance and receive the same amount of current! But you connect the way you want to, I will connect the correct way!
โDec-31-2014 02:32 PM
Bud
USAF Retired
Pace Arrow
โDec-31-2014 01:34 PM
โDec-31-2014 01:18 PM
โDec-31-2014 01:09 PM
enblethen wrote:
Coach-man that is correct.
Yes, it is slight difference in resistance.
Timay, look at a large battery room for electrical control systems. They are all wired similar to what I said. This is so you can change out battery or batteries by simply jumpering around the defective or battery(ies) that need servicing.
โDec-31-2014 08:19 AM
enblethen wrote:My point is that feeding a battery pile from one end to the other to ensure even charging is hooie. Batteries don't charge from one end to the other, all the cells charge at the same time and there is a chemical reaction inside each cell that makes the electricity. Yes, each cell will have different resistances which slightly effect charging - when one cell develops too much resistance the battery is then on its way out. If you have a pile of batteries, i.e. 2 12volters, it makes no difference if you feed the charging voltage from the ends or the sides or wherever, as long as polarity and voltage is observed.
Coach-man that is correct.
Yes, it is slight difference in resistance.
Timay, look at a large battery room for electrical control systems. They are all wired similar to what I said. This is so you can change out battery or batteries by simply jumpering around the defective or battery(ies) that need servicing.
โDec-31-2014 08:11 AM
โDec-31-2014 07:10 AM
Bud
USAF Retired
Pace Arrow
โDec-31-2014 05:13 AM
Timay wrote:enblethen wrote:Please help me understand how putting the plus and minus on opposite sides will make the first battery get a better (more equal) charge...seems to me that IT DOESN'T MATTER. Electricity runs at the speed of light and putting the plus and minus anywhere on the line that feeds both batteries will accomplish the same charge.
Downtheroad:
That is correct!
That will give a closer to equal charge and discharge.
Of course, this is more than my opinion - if it matters I am a master electrician.
Tim
โDec-30-2014 04:14 PM