โJan-13-2012 05:35 PM
โMay-30-2013 08:28 AM
โMay-30-2013 04:48 AM
mikedboyd wrote:
For 4 reasons, I traded in my Anderson on an Equalizer 1000# 4-point hitch today.
- DW could not turn the nut with my long-handle ratchet, and she has to be able to participate in the process
โMay-14-2013 04:08 AM
โMay-13-2013 09:15 PM
Mike & Tracy Boyd
โMay-06-2013 06:27 PM
BenK wrote:
What isn't or hasn't been discussed is that the regular or traditional WD Hitch
systems 'do' beat up the coupler latch over time WITHOUT the constant contact
and force of the bushings.
The dynamic forces are NOT just from braking, or acceleration, but from all directions during a common road trip over the less than pristine roads, RR crossings,potholes, etc AT SPEED
What would you guys think or guess the forces on the latch is during a severe
whoop-do ?
Where the hitch is driven downwards to stretch the bottom plate to chain to rod to bushing?
There has been reports of the bushing shattering, or when the set screws employed
that they did not hold (allowed that bracket to move)
BenK wrote:
John, you posted some pictures a while back of your trailer coupler
that had thousands of miles with a traditional WD Hitch system.
It looked very typical vs the miles on it and the latch pawl was
beat up. I've seen much worse and NOTE that is with a traditional WD Hitch system that does NOT have the constant contact that the Andersen architecture has.
โMay-06-2013 05:31 PM
Ron Gratz wrote:JBarca wrote:John, I don't know how Ed did it, but here is my approach to defining the relationship between tension and load transfer.
Hi Ed, Welcome to the discussion! When you came up with 1,000# per chain load, what are the assumptions surrounding this?
First we need to define some dimensions and variables. Let:
a = tow vehicle wheelbase
b = ball overhang (longitudinal distance from TV rear axle to ball)
c = distance from ball to mid-point between the TT's axles
d = perpendicular distance from Andersen chain to center of ball (reported by Andersen owner to be 6.5")
TW = tongue weight
LTT = load transferred to TT's axles
LF1 = load removed from TV's front axle due to TW without WD applied
LF2 = load transferred to TV's front axle when WD is activated
T = Andersen chain tension per chain
M = moment (torque) generated by Andersen chain tension (total for 2 chains)
then (assuming zero pitch-axis rotational friction between ball and coupler)
M = 2*d*T
LTT = M/c = 2*d*T/c
LF2 = LTT*(b+c)/a = 2*d*T*(b+c)/(a*c)
also
LF1 = TW*b/a
If we want to restore a load equal to some percentage (call it FALR) of that which was removed from the front axle, we have:
LF2 = LF1*FALR/100, or 2*d*T*(b+c)/(a*c) = FALR*TW*b/(a*100)
solving for chain tension (per chain) gives
T = FALR*TW*b*c/{2*d*(b+c)*100}
for example, if: b=60", c=200", d=6.5", TW=600#, and you want to restore 50% of the load removed (FALR=50)
T = 50*600*60*200/(2*6.5*260*100) = 1065# per chain
Ron
Ron G wrote:
solving for chain tension (per chain) gives
T = FALR*TW*b*c/{2*d*(b+c)*100}
JBarca wrote:
In my case I have an actual 1,400# TW and this hitch is rated that high. That is approx. 1,100# at each snap up chain using 28.5โ long WD bar or 5,225 ft. lb of torque into the receiver. The Anderson using itโs 8โ tow ball would need 7,838# total chain force to create this.
There is some error in this as my Reese Tow beast shank is longer then the Anderson shank but it getโs me in the league of feeling what chain forces are going on with the Anderson.
The 28.5โ WD bar compared to the 8โ long tow ball is the difference in the mechanical advantage of the 2 hitches for WD. The Anderson will always have to use higher chain force to get the same WD.
โMay-06-2013 12:16 PM
โMay-05-2013 09:20 PM
Mike & Tracy Boyd
โMay-05-2013 11:39 AM
โMay-05-2013 08:38 AM
eb145 wrote:
I am thinking about getting an Andersen WDH.
And I had no idea of what kind of coupler I have on my trailer.
I now know it is a Redline CA5400 coupler. And NOT the Atwood 88xxx series coupler.
I even found a little video for it:
Redline CA5400 trailer coupler at ETrailer.com
Ed
โMay-05-2013 07:12 AM
โMay-05-2013 06:59 AM
eb145 wrote:Ron Gratz wrote:JBarca wrote:John, I don't know how Ed did it, but here is my approach to defining the relationship between tension and load transfer.
Hi Ed, Welcome to the discussion! When you came up with 1,000# per chain load, what are the assumptions surrounding this?
First we need to define some dimensions and variables. Let:
a = tow vehicle wheelbase
b = ball overhang (longitudinal distance from TV rear axle to ball)
c = distance from ball to mid-point between the TT's axles
d = perpendicular distance from Andersen chain to center of ball (reported by Andersen owner to be 6.5")
TW = tongue weight
LTT = load transferred to TT's axles
LF1 = load removed from TV's front axle due to TW without WD applied
LF2 = load transferred to TV's front axle when WD is activated
T = Andersen chain tension per chain
M = moment (torque) generated by Andersen chain tension (total for 2 chains)
then (assuming zero pitch-axis rotational friction between ball and coupler)
M = 2*d*T
LTT = M/c = 2*d*T/c
LF2 = LTT*(b+c)/a = 2*d*T*(b+c)/(a*c)
also
LF1 = TW*b/a
If we want to restore a load equal to some percentage (call it FALR) of that which was removed from the front axle, we have:
LF2 = LF1*FALR/100, or 2*d*T*(b+c)/(a*c) = FALR*TW*b/(a*100)
solving for chain tension (per chain) gives
T = FALR*TW*b*c/{2*d*(b+c)*100}
for example, if: b=60", c=200", d=6.5", TW=600#, and you want to restore 50% of the load removed (FALR=50)
T = 50*600*60*200/(2*6.5*260*100) = 1065# per chain
Ron
Now this calculation makes me smile - it has been many years since my Statics and Dynamics classes! I especially like it because it shows my main assumption might actually be correct. But I will disclose how I came up with the 1,000# per chain estimate: several posts discussed a similar setup as mine that had various real measurements that showed about 1,000# per chain transferring the correct amount of weight to the front axle.
Ron's comment about the safety spec requiring that force for only 5 seconds is very relevant new information for me.
So a simple comparison (using rough estimate numbers - not exact) might be like this:
8 hours = 28,800 seconds. Let's round up to 30,000 seconds for a long day of driving.
And I have a 14,000# rated coupler.
Safety spec requires 3X the coupler rating for 5 seconds:
42,000# force for 5 seconds required by safety spec.
Andersen WDH exerts a constant baseline force:
2,000# force for 30,000 seconds
(Caution: THIS 2,000# force number will vary significantly for each rig)
Traditional WDH exerts a constant baseline force closer to zero.
Both couplers experience lots of dynamic forces from road use in all directions on top of the baseline (static) force.
So the obvious difference (as everyone following this thread knows and I am catching up on) is the Andersen WDH has a constant baseline force applied to the coupler in a rear direction.
And the baseline force on the coupler will vary significantly per rig depending on how much force is needed to get proper weight distribution.
And one coupler type (Atwood 88xxx series) so far has been shown to not like that constant baseline force.
Very enlightening.
And my 1,000 lbs per chain assumption is quite different from John's calculations that show almost 3,000 lbs. per chain for his 1,400# tongue weight setup. John's calculations.
I guess for now the bottom line for me is the more you have to compress the urethane bushing for proper weight distribution the more baseline force you are putting on the coupler. Know your coupler and keep an eye on it.
I just went outside, laid down on the gravel and looked "up" at the inside of my coupler for the first time. (Sunday morning in my pajamas:) )
What a great forum.
Ed
โMay-05-2013 06:49 AM
eb145 wrote:
Snip...
I just went outside, laid down on the gravel and looked "up" at the inside of my coupler for the first time. (Sunday morning in my pajamas:) )
What a great forum.
Ed
โMay-05-2013 06:43 AM
Ron Gratz wrote:JBarca wrote:John, I don't know how Ed did it, but here is my approach to defining the relationship between tension and load transfer.
Hi Ed, Welcome to the discussion! When you came up with 1,000# per chain load, what are the assumptions surrounding this?
First we need to define some dimensions and variables. Let:
a = tow vehicle wheelbase
b = ball overhang (longitudinal distance from TV rear axle to ball)
c = distance from ball to mid-point between the TT's axles
d = perpendicular distance from Andersen chain to center of ball (reported by Andersen owner to be 6.5")
TW = tongue weight
LTT = load transferred to TT's axles
LF1 = load removed from TV's front axle due to TW without WD applied
LF2 = load transferred to TV's front axle when WD is activated
T = Andersen chain tension per chain
M = moment (torque) generated by Andersen chain tension (total for 2 chains)
then (assuming zero pitch-axis rotational friction between ball and coupler)
M = 2*d*T
LTT = M/c = 2*d*T/c
LF2 = LTT*(b+c)/a = 2*d*T*(b+c)/(a*c)
also
LF1 = TW*b/a
If we want to restore a load equal to some percentage (call it FALR) of that which was removed from the front axle, we have:
LF2 = LF1*FALR/100, or 2*d*T*(b+c)/(a*c) = FALR*TW*b/(a*100)
solving for chain tension (per chain) gives
T = FALR*TW*b*c/{2*d*(b+c)*100}
for example, if: b=60", c=200", d=6.5", TW=600#, and you want to restore 50% of the load removed (FALR=50)
T = 50*600*60*200/(2*6.5*260*100) = 1065# per chain
Ron
โMay-04-2013 08:24 PM
PHS79 wrote:
Our TT has the 81911 and we have the Andersen hitch last year we put on only about 2000 miles. If we still have the TT and the couple would have to be replaced at some point down the road, I would install a Bulldog hitch. We have Bulldog couplers on numerous trailers, one of which has more than 100,000 miles on it and still has the original coupler.
I do a "pre trip inspection" everytime that we are packing for a weekend. Because of the issues that some have had with the Andersen hitch and different couplers, I make sure to check the coupler just to look for anything out of the ordinary.